(k+1)x^2+5x+2=0

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Solution for (k+1)x^2+5x+2=0 equation:


Simplifying
(k + 1) * x2 + 5x + 2 = 0

Reorder the terms:
(1 + k) * x2 + 5x + 2 = 0

Reorder the terms for easier multiplication:
x2(1 + k) + 5x + 2 = 0
(1 * x2 + k * x2) + 5x + 2 = 0

Reorder the terms:
(kx2 + 1x2) + 5x + 2 = 0
(kx2 + 1x2) + 5x + 2 = 0

Reorder the terms:
2 + kx2 + 5x + 1x2 = 0

Solving
2 + kx2 + 5x + 1x2 = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + kx2 + 5x + -2 + 1x2 = 0 + -2

Reorder the terms:
2 + -2 + kx2 + 5x + 1x2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + kx2 + 5x + 1x2 = 0 + -2
kx2 + 5x + 1x2 = 0 + -2

Combine like terms: 0 + -2 = -2
kx2 + 5x + 1x2 = -2

Add '-5x' to each side of the equation.
kx2 + 5x + -5x + 1x2 = -2 + -5x

Combine like terms: 5x + -5x = 0
kx2 + 0 + 1x2 = -2 + -5x
kx2 + 1x2 = -2 + -5x

Add '-1x2' to each side of the equation.
kx2 + 1x2 + -1x2 = -2 + -5x + -1x2

Combine like terms: 1x2 + -1x2 = 0
kx2 + 0 = -2 + -5x + -1x2
kx2 = -2 + -5x + -1x2

Divide each side by 'x2'.
k = -2x-2 + -5x-1 + -1

Simplifying
k = -2x-2 + -5x-1 + -1

Reorder the terms:
k = -1 + -2x-2 + -5x-1

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